the kinetic energy of an object of mass M moving with a velocity of 5 metre per second is 25 J what will be its kinetic energy when its velocity is doubled what will be its kinetic energy when its velocity is increased 3 times
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kinetic energy = 1/2mv^2.
when velocity is doubled then kinetic energy becomes 4 times as K. E= 1/2m*(2v) ^2
=1/2 m 4v^2
so new K. e=25*4=100
similarly kinetic energy becomes 9 times when velocity is tripled
that is 9*25= 225
when velocity is doubled then kinetic energy becomes 4 times as K. E= 1/2m*(2v) ^2
=1/2 m 4v^2
so new K. e=25*4=100
similarly kinetic energy becomes 9 times when velocity is tripled
that is 9*25= 225
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