Physics, asked by roneei, 20 hours ago

The kinetic energy of an object of mass m, moving with a velocity of 5 m/s is 25 J. What will be its kinetic energy when its speed is doubled? it is given here doubled not tripled​

Answers

Answered by Okhey
10

⇝Given :)

  • Initial Velocity = 5 m/s
  • Kinetic energy = 25 J
  • Its speed is doubled .

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⇝To Find :)

  • Find kinetic energy when speed is doubled .

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⇝Formula Used :)

Kinetic Energy :-

{\large{\orange{\bigstar \:  \: {\blue{\underbrace{\underline{\orange{\bf{K.E =   \frac{1}{2}  \times m {v}^{2} }}}}}}}}}

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⇝Solution :)

{\green{❒}}{\underline{\bf{ First ,finding \:  the \:  mass  :}}}

{\large{:{\longmapsto{\bf{K.E = \frac{1}{2} \times m {v}^{2}   }}}}}

{\large{:{\longmapsto{\bf{25 = \frac{1}{2} \times m \times  {5}^{2}   }}}}}

{\large{:{\longmapsto{\bf{25 = \frac{1}{2} \times m \times25   }}}}}

{\large{:{\longmapsto{\bf{25 \times 2 = 1 \times m \times  25  }}}}}

{\large{:{\longmapsto{\bf{50 =  m \times  25  }}}}}

{\large{:{\longmapsto{\bf{M ={\cancel  \frac{50}{25} }}}}}}

{\large{\purple{:{\longmapsto{\overline{\underline{\boxed{\bf{Mass = 2 \:  kg}}}}}}}}}

{\pink{❒}}{\underline{\bf{  Than, \:  K.E  \: if  \: speed \:  is \:  doubled:}}}

Doubled Speed = 5 × 2 = 10 m/s

Mass = 2kg

Kinetic Energy = ?

{\large{:{\longmapsto{\bf{K.E = \frac{1}{2} \times m {v}^{2}   }}}}}

{\large{:{\longmapsto{\bf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \frac{1}{2} \times 2 \times  {10}^{2}   }}}}}

{\large{:{\longmapsto{\bf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{1}{2} \times 2 \times100 }}}}}

{\large{:{\longmapsto{\bf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{1}{2} \times 200 }}}}}

{\large{:{\longmapsto{\bf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{1}{\cancel{2}} \times{\cancel{ 200}} }}}}}

{\large{\purple{:{\longmapsto{\overline{\underline{\boxed{\bf{K.E = 100  \: Joules}}}}}}}}}

{\orange{✧}}{\underline{\bf{ Therefore :}}}

{\pmb{\blue{\underline{\orange{\underline{\red{\mathfrak{New  \: Kinetic \:  Energy = 100  \: Joules}}}}}}}}

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  • @Okhey
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