the kinetic energy of an object of mass M moving with a velocity of 5 m s-1 is 25 j.what will be its kinetic energy when its velocity is doubled what will be its kinetic energy when its velocity is increased three times
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mass=m
velocity=5m/s
k(e)=25J
K(e=1/2mv^2
1/2*m*5^2=25
m/2*25=25
m=25*2/25
m=50/25
m=2kg
when v is doubled
k(e)=1/2*2*10^2
k(e)=100J
when velocity is increased 3 times
k(e)=1/2*2*5^3
k(e)=125J
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