Physics, asked by Anonymous, 11 months ago

The kinetic energy of an object of mass, m moving with a velocity of 5 ms 1 is 25 What will be its kinetic energy when its velocity is doubled? What will be its kine energy when its velocity is increased three times.

Answers

Answered by Anonymous
110

Answer:-

Known Terms:-

m = Mass of the object

v = Velocity of the object

K.E = Kinetic energy attain by object.

j = Joule.

Given:-

Kinetic energy attain by object, K.E = 25 joule.

Velocity of the object, v = 5 m/s.

To Find:-

Kinetic energy when velocity in increased three times.

Solution:-

We know that K.E

= \frac{1}{2} mv^2

⇒ K.E = \frac{1}{2} mv^2

⇒ 25 = \frac{1}{2} m 5^2

⇒ m = 2 kg

1st Case

If velocity is doubled

then,

velocity of the object = 10 m/s

mass os the object = 2 kg

⇒ K.E = \frac{1}{2} mv^2

⇒ K.E = \frac{1}{2} 2 × 10²

⇒ K.E = 100 joule.

2nd Case

If velocity is three times

Then,

velocity of the object = 15 m/s

mass os the object = 2 kg

⇒ K.E = \frac{1}{2} mv^2

⇒ K.E = \frac{1}{2} 2 × 15²

⇒ K.E = 225 joule.

Hence, kinetic energy  when its velocity is increased three times 225 J.

Answered by Anonymous
40

HOLA MATE

ANSWER:-

Let the mass be m

v = 5m/s

K.E = 25 J

K.E = 1/2 mv^2

25 = 1/2 m (5)^2

25 x 2 = 25m

m = 2 kg

Now if the velocity becomes 3 times then the velocity is 3 x 5 = 15m/S

Now new K.E = 1/2 x 2 x 15^2

= 225 J

❤HOPE IT HELPS,❤

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