The kinetic energy of any object is changes 25%.Find the percentage change of linear momentum
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Answered by
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momentum will change by 5 %
ashisingh65289:
if kinetic energy change is 2.5%...then the %age change in linear momentum
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0
Hey dear,
◆ Answer-
∆p/p = 12.5 %
◆ Explanation-
# Given-
∆KE/KE = 25 %
# Solution-
Let m be the mass of the object and v be initial velocity.
Kinetic energy is given -
KE = 1/2 mv^2
As p = mv,
KE = p^2 / 2m
Differentiating both sides, we get -
∆KE/KE × 100 = 2 ∆p/p × 100
∆p/p × 100 = 1/2 × ∆KE/KE × 100
∆p/p × 100 = 1/2 × 25 % × 100
∆p/p × 100 = 12.5
Change in momentum will be 12.5 %.
Hope this helps you...
◆ Answer-
∆p/p = 12.5 %
◆ Explanation-
# Given-
∆KE/KE = 25 %
# Solution-
Let m be the mass of the object and v be initial velocity.
Kinetic energy is given -
KE = 1/2 mv^2
As p = mv,
KE = p^2 / 2m
Differentiating both sides, we get -
∆KE/KE × 100 = 2 ∆p/p × 100
∆p/p × 100 = 1/2 × ∆KE/KE × 100
∆p/p × 100 = 1/2 × 25 % × 100
∆p/p × 100 = 12.5
Change in momentum will be 12.5 %.
Hope this helps you...
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