the kinetic energy of photoelectron when a radiation hit the metal is (v.=10³)
(1) 2.14×10^-18
(2) 6.73× 10^-24
(3) 5.96×10^-30
(4) 7.12×10^-34
Answers
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Explanation:
Violet light of wavelength 400 nm ejects electrons with a maximum kinetic energy of 0.860 eV from sodium metal
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I don't know the exact answer because I have not studied that yet
but I have the similar question so you can correlate with this this question and get your answer
^_^ :-)
QUESTION
The threshold frequency v ofor a metal is 7.0×1014 s−1 . Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0×10^15 s −1 hits the metal.
ANSWER :
Given that,
v o = 7.0×10^14 s^−1
v = 1.0 × 10^15 s^−1
As we know, hv=hv o + 1/2 mv^2
i.e. h(v−v o)= K.E.
∴K.E. =(6.626 × 10^−34) × (1.0×10^15 − 7.0 × 10^14) = 6.626 × 10^−34 × 10^14(10−7)
∴K.E = 19.878×10^−20 J
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