Physics, asked by piyushsikarwar35, 4 hours ago

the kinetic energy of photoelectron when a radiation hit the metal is (v.=10³)
(1) 2.14×10^-18
(2) 6.73× 10^-24
(3) 5.96×10^-30
(4) 7.12×10^-34 ​

Answers

Answered by Anonymous
34

Explanation:

Violet light of wavelength 400 nm ejects electrons with a maximum kinetic energy of 0.860 eV from sodium metal

Answered by harshjadhav71
1

I don't know the exact answer because I have not studied that yet

but I have the similar question so you can correlate with this this question and get your answer

^_^ :-)

QUESTION

The threshold frequency v ofor a metal is 7.0×1014 s−1 . Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0×10^15 s −1 hits the metal.

ANSWER :

Given that,

v o = 7.0×10^14 s^−1

v = 1.0 × 10^15 s^−1

As we know, hv=hv o + 1/2 mv^2

i.e. h(v−v o)= K.E.

∴K.E. =(6.626 × 10^−34) × (1.0×10^15 − 7.0 × 10^14) = 6.626 × 10^−34 × 10^14(10−7)

∴K.E = 19.878×10^−20 J

Similar questions