Question

The king, queen and jack of spade are removed from a deck of 52 cards and then well shuffled. One card is selected from the remaining cards. Find the probability of getting (i) a club (ii) a queen (iii) a jack of hearts.

Answer 1

Answer:

A deck of playing cards consists of 52 cards out of which 26 are black cards and other 26 are red cards . Where as  red cards consist of 13 cards of heart (♥),  13 cards of diamond(♦) and black cards consists of 13 cards of spades(♠) and 13 cards of club(♣).

King, queen and jack are called face cards so total face cards= 12

Here, King, queen and jack of club are removed from the Deck of 52 playing cards.

So remaining cards in deck= 52-3=49

Total number of outcomes= 49

(i)

We know that there are 13 cards of club. After removing king ,queen and jack of club only 10 club cards are left in the deck.

Let E3 = event of getting a club

Number of favourable outcomes to  E3= 10

Required probability P(E3)= 10/49

(ii)

We know that there are 4 queen in a deck. After remove removing a queen of club we left with  3 queen.

Let E2 = event of getting a queen

Number of favourable outcomes to  E2= 3

Required probability P(E2)= 3/49

(iii)

we know that there are 13 cards of heart.

Let E1 = event of getting a heart

Number of favourable outcomes to E1= 13

Required probability P(E1)= number of available outcomes/total number of outcomes

P(E1)= 13/49

Answer 2

Answer:

n(s)=49

a) a club

A={including A king queen and jack and remaining cards}

n(A)=13

P(A)=n(A)/n(s)

P(A)=13/49

b)a queen

B={there are 3 queen in remaining cards}

n(B)=3

P(B)= n(B)/n(s)

P(B)=3/49

c) a jack of hearts

n(C)= {there is only one jack in heart}

n(C)=1

P(C)=n(C)/n(s)

P(C)=1/49

Step-by-step explanation:

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