Question

The Ksp of manganese(II) carbonate, MnCO3, is 2.42⋅10−11. What is the solubility of this compound in g/L?

Answer 1

Answer:

The solubility of this compound is$5.6320\times 10^{-4} g/L$.

Explanation:

$MnCO_3\rightleftharpoons Mn^{2+}+CO_{3}^{2-}$

                       S  S

Solubility product of manganese(II) carbonate =$K_{sp}=2.42\times 10^{-11} M^2$

$K_{sp}=S\times S=S^2=2.42\times 10^{-11} M^2$

$S=0.49\times 10^{-5} M=[MnCO_3]$

The solubility of manganese(II) carbonate =$0.49\times 10^{-5} mol/L$

The solubility of this compound in g/L =$0.49\times 10^{-5} mol/L\times 114.94 g/mol=5.6320\times 10^{-4} g/L$

The solubility of this compound is$5.6320\times 10^{-4} g/L$.