the l.c.m of two numbers is 168 and their h.c.f is 12 if the difference between the number is 60 what is the sum of the numbers
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Step-by-step explanation:
Two numbers Ax, Bx
Lcm of them ABx
Hcf of them x
Multiple of them ABx^2
Now ,
Lcm/ hcf = AB
This AB is the product of the ratio of the numbers
168÷12=14
AB =14
Break the product in multiple
14=1*14
14= 2*7
Now see we get only two cases
In first case: numbers are 12*1 =12 and 14*12 = 168
Diff is 168 -12 =156 so these two numbers didn't satisfy the condition of the difference between no 60
In second case numbers are 12*2 =24, and 12*7=84
Diff of the numbers is 84–24=60 it satisfy the condition
So the numbers are 24 and 64
So the total of the number 24+64=88
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