Question

The lager of two supplementery angles the smaller by18*.find the angles.

Answer 1

heya!! mate^_^

your answer is - - - - -

let 1st angle=x

let 2nd angle=x-18

A.T.Q,

$x+x-18=180$

$2x-18=180$

$2x=180+18$

$2x= 198$

$x=198/2$

$x= 99$

so,

angles will be

x=99°

x-18= 99-18= 81°

Answer 2

$supplementary \: angle \: is \: 180 \\ \\ \\ (x ) \: + (x + 18) = 180 \\ \\ 2x \: = 180 - 18 \\ \\ 2x = 162 \\ \\ x = 81 \\ \\ other \: angle \: or \: greater \: angle \: is \: 99$