Question

The larger of the two supplementary angles exceed the smaller by 18 degree find them

Answer 1

let one angle is X
and other angle is X + 18
then. angle 1+angle 2 = 180°
then. X +(X+18°)=180 °
X + X +18°=180°
2X +18°= 180°
2X=180°-18°
X=162/2
X = 81°
first angle is 81° and other angle is 81°+18°=99°

Answer 2

Answer:

Step-by-step explanation:

Let the smaller angle be x,

Then the largest angle is x+18,

x+x+18=90

2x+18=90

2x=90-18

2x=72

x=72/2

x=36

Therefore,

The smaller angle be x,

=36 degree

Then the largest angle is x+18,

=(36 +18)degree

=54 degree