the larger of two supplementary angles exceed s the smaller by 18 degree find them
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Let the supplementary angles be x and y (x>y)
Then. x+y=180. ………(1)
Now according to the question,
x-y=18. ………(2)
y=x-18. ………(3)
Substituting value of y from equation (3) in equ. (1)
We get
x+y=180
x+x-18=180
2x-18=180
2x=180+18
2x=198
x=198/2
x=99
Substituting value x in equation (3)
y=x-18
y=99-18
y=81
The required angles are 99 and 81
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Then. x+y=180. ………(1)
Now according to the question,
x-y=18. ………(2)
y=x-18. ………(3)
Substituting value of y from equation (3) in equ. (1)
We get
x+y=180
x+x-18=180
2x-18=180
2x=180+18
2x=198
x=198/2
x=99
Substituting value x in equation (3)
y=x-18
y=99-18
y=81
The required angles are 99 and 81
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Answered by
9
Step-by-step explanation:
HLW MATE HERE IS YOUR CORRECT ANSWER.......
Let the larger angle be 'x' and the smaller one be 'y'
ATQ,
x =y +18 ---------------------(1)
We know that, sum of supplementary angles =180°
x+y=180°---------------------(2)
SUBSTITUTE x=y+18 in eq (2)
y+18+y=180°
2y=180-18
2y=162
y=162/2
✓y=81
x=81+18
=99
THEREFORE,
THE ANGLES ARE 81 AND 99
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