Question

The larger of two supplementary angles exceeds the smaller by 18 degree. Find them​

Answer 1

Let the larger angle = x°

Let the smaller angle = y°

According to question

x + y = 180° (Equation 1)

x = y + 18° (Equation 2)

By putting value of x in (Equation 1)

x + y = 180°

y + 18° + y = 180°

2y + 18° = 180°

2y = 180° - 18

2y = 162°

y = $\dfrac {162^{\circ}}{2}$

y = 81°

So,

x = y + 18°

x = 81° + 18°

x = 99°

Therefore,

Larger angle (x) = 99°

Smaller angle (y) = 81°

Answer 2

Answer:

Let the larger angle = x°

Let the smaller angle = y°

According to question

x + y = 180° (Equation 1)

x = y + 18° (Equation 2)

By putting value of x in (Equation 1)

x + y = 180°

y + 18° + y = 180°

2y + 18° = 180°

2y = 180° - 18

2y = 162°

y = \dfrac {162^{\circ}}{2}

2

162

∘

y = 81°

So,

x = y + 18°

x = 81° + 18°

x = 99°

Therefore,

Larger angle (x) = 99°

Smaller angle (y) = 81°

Explanation:

Hope this answer will help you.