Question

The larger of two supplementary angles exceeds the smaller by 18°.find the angels

Answer 1

large angle =x

small angle =x-18

So,

x+x-18=180

→2x=198

→x=198/2

→x=99

large angle=99

small angle=(99-18)=81

Answer 2

Answer:

Step-by-step explanation:

Let the smaller angle be x,

Then the largest angle is x+18,

x+x+18=90

2x+18=90

2x=90-18

2x=72

x=72/2

x=36

Therefore,

The smaller angle be x,

=36 degree

Then the largest angle is x+18,

=(36 +18)degree

=54 degree