The larger of two supplementary angles exceeds the smaller by 18 degree find the angle.
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Answers
Answered by
6
Heya user
Here ia your answer !!
Let the bigger supplementary angle be x° .
So , the smaller angle is ( 180 - x )°
So , ATQ ,
x = ( 180 - x ) + 18
=> x = 198 - x
=> 2x = 198
=> x = 99 .
So , the larger angle is 99° .
So , the smaller angle is = ( 180 - 99 )° = 81° .
Hope it helps !!
Here ia your answer !!
Let the bigger supplementary angle be x° .
So , the smaller angle is ( 180 - x )°
So , ATQ ,
x = ( 180 - x ) + 18
=> x = 198 - x
=> 2x = 198
=> x = 99 .
So , the larger angle is 99° .
So , the smaller angle is = ( 180 - 99 )° = 81° .
Hope it helps !!
Answered by
2
Let us assume small angle as x
According to question
x+x+18=180
2x+18=180
2x=162
X=81
Therefore,
Smaller angle is 81, larger angle is 99.
According to question
x+x+18=180
2x+18=180
2x=162
X=81
Therefore,
Smaller angle is 81, larger angle is 99.
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