the larger of two supplementary angles exceeds the smaller by 18. Find the angles.
Answers
Answered by
47
Hey Mate!
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Here is your answer :
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Let the smaller angle be x
larger angle be x + 18
Sum of supplementary angles = 180
x + x + 18 = 180
2x + 18 = 180
2x = 180 - 18
2x = 162
x = 162 / 2
x = 81
The other angle = 81 + 18 = 99
HOPE THIS HELPS U...
~~~~~~~~~
Here is your answer :
===============================
Let the smaller angle be x
larger angle be x + 18
Sum of supplementary angles = 180
x + x + 18 = 180
2x + 18 = 180
2x = 180 - 18
2x = 162
x = 162 / 2
x = 81
The other angle = 81 + 18 = 99
HOPE THIS HELPS U...
Answered by
10
Let the smaller angle be x, then the larger one is 18+x.
Sum of supplementary angles = 180°
So, x+(18+x) = 180°
So, 2x+18=180
or, 2x=180-18
or, 2x=162°
Hence, x = 81°.
Hence, smaller angle is 81°, and the larger one is 81+18° or 99°.
Sum of supplementary angles = 180°
So, x+(18+x) = 180°
So, 2x+18=180
or, 2x=180-18
or, 2x=162°
Hence, x = 81°.
Hence, smaller angle is 81°, and the larger one is 81+18° or 99°.
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