Question

The larger of two supplementary angles exceeds the smaller by
48° Find the angles???

Answer 1

Let, the first angle be x°.

Then, the second angle will be (x-48°).

Since, the angles are supplementary.

So,

$\: \: \: \: \: x + x - {48}^{o} = {180}^{o} \\ 2x = {180}^{o} + {48}^{o} \\ x = \frac{ {228}^{o} }{2} = {114}^{o}$

∴ First Angle = x = 114°

Second Angle = x - 48° = 66°

Hope It Helps :))