the larger of two supplementary angles exceeds the smaller by 18 degree .find them
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the the smaller angle be x, then greater one = x+18,
x+x+18=180(sum of 2 supplementary angles)
2x+18=180
2x=180-18
2x=162
x=162/2
x=81
the measure of greater one
81+18=99
sanjith78:
tq
Answered by
3
my answer to this question is 99
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