Question

The larger of two supplementary angles exceeds thrice the smaller by 20 degrees find them

Answer 1

Let the smaller angle be x,
Then the largest angle is 3x+20,

x+3x+20=90
4x+20=90
4x=90-20
4x=70
x=70/4
x=17.5

Therefore,
The smaller angle be x,
=17.5 degree
Then the largest angle is 3x+20,
=(3×17.5)+20 degree
=52.5+20 degree
=72.5 degree

Answer 2

Answer:

Step-by-step explanation:

Let the smaller angle be x

Let the larger angle be x+20

As it exceeds thrice the smaller

Let it be 3x+20

As it is supplementary angles, they sum upto 180°

x+3x+20=180

4x+20=180

4x=180-20

4x=160

x=160/4

x=40

Smaller angle=40°

3x+20

3(40)+20

120+20

140

Therefore the smaller angle is 40° and the larger angle is 140°