Math, asked by deoBorde, 1 year ago

The largest 5 digit number exactly divisible by 91 is:

Answers

Answered by HurricaneKartrina
46
5 digit largest number is 99999 
99999/91 = 1098 81/91 
quotient is 1098 and remainder is 81 
subtract 81 from 99999 
99999 – 81 = 99918 required number 

if same question continued for 5 digit smallest number 
you can straight away take remainder as 81 

or calculates 
5 digit smallest number is 10000 
10000/91 = 109 81/91 
then required number is (10000 + (91 – 81) = 10010 
(91 – 81) is difference in divisor and remainder to be added to get required number.

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Answered by sanjiv39
3

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