Question

the largest number by which on dividing the number 1356, 1868 12764 the remainder is 12 in all cases

Answer 1

Hii friend,

1356 - 12 = 1344

1868 -12 = 1856

12764 - 12 = 12752

Prime factorisation of 1344 = 2 × 2 × 2 × 2 × 797.

Prime factorisation of 1856 = 2 × 2 × 2 × 2 × 2 × 2 × 29.

Prime factorisation of 12752 = 2 × 2 × 2 × 2 × 2 ×2 × 3 × 7.

HCF of 1344 , 1856 and 12752 = 2× 2 × 2 × 2 = 16

hence,

16 is the largest Number that Divides 1356 , 1868 and 12764 leaving Remainder 12 .


HOPE IT WILL HELP YOU..... :-)

Answer 2

hye

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we have yo find The largest number by which on dividing the number 1356, 1868 12764 the remainder is 12 in all cases

so first let us subtract 12 from each case

=>1356 - 12  = 1344

=>1868 - 12 = 1856

=>12764 -12 = 12752


now let us fnd the  H.C.F. of 1344, 1856 and 12752

=>facors of 12752 = 1, 2, 4, 8, 16, 797, 1594, 3188, 6376, 12752

=>facotrs of 1344= 1,2,3,4,6,7,8,12,14,16,21,24,28,32,42,48,56,64,84,96,112,168,192,224,336,448,672


=>factors of 1856=  1,2,4,8,16,29,32,58,64,116,232,464,928,1856

hcf = 16

hence 16 is the number   by which on dividing the number 1356, 1868 12764 the remainder is 12 in all cases

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hope it help u........