Question

The largest number which divides 224 and 118leaving remainders 4and3 respectively is

Answer 1

Answer: 5

Step-by-step explanation:

Since, 4 and 3 are the remainders of 224 and 118, respectively.

Thus, after subtracting these remainders from the numbers, we have the numbers 220 = (224 – 4), 115 = (118−3), which is divisible by the required number.

Now, required number = HCF of 220, 115 [Since we need the largest number] For this, 220 = 115×1+95 [∵ dividend = divisor × quotient + remainder]

⟹ 115 = 95×1+20

⟹ 95 = 20×4+15

 ⟹ 20 = 15×1+5

⟹ 15 = 5×3+0

∴ HCF = 5

Hence, 5 is the largest number which divides 224 and 118, leaving remainders 4 and 3.

Answer 2

Answer:

5 is the answer

Step-by-step explanation:

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