Question

The largest number which divides 245 and 1029 leaving remainder 5 in each case is

Answer 1

Original number 1 = 245 - 5 = 240

Original number 2 = 1029 - 5 = 1024

largest number that divides 245 and 1029 leaving remainder 5 in both cases = HCF(240,1024)

==> HCF(240,1024) = 16

Hence, the answer is 16

Answer 2

Answer:

16 is your answer.

Step-by-step explanation:

245-5=240

1029-5=1024

find the hcf of 1024,240 by prime factorisation

240=2^4*3*5

1024=2^10

the HCF 2^10=16

your and is 16

check 245/16=30+5remainder

1029/16=64+5remainder

please mark in brainlist answer