The largest number which divides 281 and 1249 leaving remainder 5 and 7 respectively is -
Answers
Answer:
Step-by-step explanation:
To find the largest number which when divided 285 and 1249 leaving the remainder 9 and 7 respectively. First we subtract the remainder from the given numbers and then calculate the HCF of new numbers.
SOLUTION :
Given numbers are 285 and 1249 and remainders are 9 and 7 respectively. Then new numbers after subtracting remainders are :
285 – 9 = 276
1249 – 7 = 1242.
The required number is HCF of 276 and 1242.
HCF by prime factorization method :
Prime factorization of 276 = 2×2×3×23 = 2² × 3¹ × 23¹
Prime factorization of 1242 = 2×3×3×3×23 = 2¹ × 3³ × 23¹
HCF of 276 and 1242 = 2¹ ×3¹×23¹
= 6 × 23 = 138
[HCF of two or more numbers = product of the smallest power of each common prime factor involved in the numbers.]
HCF of 276 and 1242 is 138.
Hence, the required greatest number which divides 285 and 1249 leaving remainders 9 and 7 respectively is 138.
HOPE THIS WILL HELP YOU…
Answer:
see the above attachment
Step-by-step explanation:
the ans is
138 is the largest number which divides 281 and 1249 leaving remainder 5 and 7
