Question

the largest number which divides 546 and 748 and leaving the remainder 6 and 8 respectively​

Answer 1

Answer:

The largest number which divides 546 and 748 and leaving the remainder 6 and 8 respectively is 20.

Explanation:

this means, 546 - 6 = 540

and              748 - 8 = 740

are completely divisible by the required no.

so now we will find the HCF

The HCF of 540 and 740 is 20.

Therefore the largest number which divides 546 and 748 and leaving the remainder 6 and 8 respectively​ is 20

Hope it helps...........