Math, asked by MathMaster2005, 8 months ago

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively

Answers

Answered by Anonymous
1

Answer:

13 is the largest number which divides 70 and 125, leaving remainders 5 and 8 respectively

Step-by-step explanation:

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively  :

largest number that divides two numbers = HCF

let's take HCF = x

70/x leaves remainder 5

125/x leaves remainder 8

70-5 = 65

125- 8 = 117

70/x = no remainder

117/x = no remainder

HCF of 65 , 117 = 13

The largest number which divides 70 and 125, leaving remainders 5 and 8 respectively  is 13

Answered by Anonymous
0

GIVEN:-

The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively.

FIND:-

What is the number = ?

SOLUTION:-

Here,

when the number divides 70 leaves remainder as 5. So, 70-5 = 65

and

when the number divides 125 leaves remainder as 8. So, 125 - 8 = 117

Now, let us find the HCF of 65 and 117.

Since, 117>65

 \tt \therefore117 = 65 \times 1 + 52

 \tt \implies65 = 52 \times 1 + 13

 \tt \implies 52  = 13\times 4 + 0

Hence, remainder is become 0.

Thus, 13 is the HCF of 65 and 117.

Hence, \boxed{\tt13} is the required no. which divides 70 and 125 leaving remainder 5 and 8 respectively.

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