The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is
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Answered by
3
ur answer is 13
Explanation: Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers
65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.
Now required number = H.C.F of (65,117)
117=65×1+52
65=52×1+13
52=13×4+0
H.C.F(65,117)=13
hope it's helps you
Explanation: Since 5 and 8 are the remainders of 70 and 125, respectively. Thus after subtracting these remainders from the numbers, we have the numbers
65 = (70 − 5), 117 = (125 − 8) which is divisible by the required number.
Now required number = H.C.F of (65,117)
117=65×1+52
65=52×1+13
52=13×4+0
H.C.F(65,117)=13
hope it's helps you
Answered by
1
Answer:
13
Step-by-step explanation:
Since, 5 and 8 are the remainders of 70 and 125, respectively.
Thus, after subtracting these remainders from the numbers, we have the numbers
65 = (70-5), 117 = (125 – 8),
which is divisible by the required number.
Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 and 8. Please mark as brainliest
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