The largest number which divides 70 and 125, leaving remainders 5 and 8, respectively, is
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Answer:
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Step-by-step explanation:
13
(a) Since, 5 and 8 are the remainders of 70 and 125, respectively. Thus, after subtracting these remainders from the numbers, we have the numbers 65 = (70-5), 117 = (125 – 8), which is divisible by the required number. Hence, 13 is the largest number which divides 70 and 125, leaving remainders 5 amnd 8.
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The largest number by which x , y divisible and gives the remainder a and b is the HCF of ( x - a ) and ( y - b)
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According to the given problem ,
The largest number which divides
70 and 125 leaving remainders 5 and
8 respectively are
HCF of ( 70 - 5 ) = 65 and
( 125 - 8 ) = 117
65 = 5 × 13
117 = 3 × 3 × 13
HCF ( 65 , 117 ) = 13
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