Math, asked by skm17m, 10 months ago

the largest number which is divides 85 and 150 leaving remainder 4 and 6 respectively is

Answers

Answered by sharmatanmay4002
0

Answer:

85-4 = 81 and 150 - 6 = 144

Step-by-step explanation:

so now , factorize 81 and 144 .

81 = 3 * 3 * 3 * 3

144 = 2 * 2 * 2 * 2 * 3 * 3

so the largest number is 3 * 3 = 9

Answered by saisripurna89
0

Answer:

Step-by-step explanation:

Let X be the largest number divided with 85 leaves the remainder 4

and divided with 150 leaves the remainder 6

Dividend = divisor* Quotient + Remainder

Subtract the remainders we get the numbers like this

85-4=81

150-6=144

Now find the HCF of these two we will get the number

AS we have to find Largest number we use HCF

HCF(81,144)

We shall take using factorization method

81 = 3*3*3*3 = 3^4

144 =2*2*2*2*3*3 = 2^4 * 3^2

Take the prime numbers with least power and is present in all sets.

3 is the prime number common to all given numbers.

Least power of 3 is 3^2

So Largest number is "9"

Hope this will help you

Similar questions