Question

the last digit of 2^22+5^55+8^88 is:

Answer 1

Step-by-step explanation:

The answer is 8:

First, let us establish the first 16 terms of the sequence 2^n, from n = 1:

2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536

As we can see, the last digits of the numbers when n = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 and 16 are 2, 4, 8, 6, 2, 4, 8, 6, 2, 4, 8, 6, 2, 4, 8 and 6 respectively.

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Answer 2

Answer:

IT IS 5

Step-by-step explanation:

unit of digit of 2^22 is 4

unit digit of 5^55 is 5

unit digit of 8^88 is 6

adding will give 15

unit digit is therefore 5....

hope it helps