the last digit of 2^22+5^55+8^88 is:
Answers
Answered by
2
Step-by-step explanation:
The answer is 8:
First, let us establish the first 16 terms of the sequence 2^n, from n = 1:
2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536
As we can see, the last digits of the numbers when n = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15 and 16 are 2, 4, 8, 6, 2, 4, 8, 6, 2, 4, 8, 6, 2, 4, 8 and 6 respectively.
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Answered by
1
Answer:
IT IS 5
Step-by-step explanation:
unit of digit of 2^22 is 4
unit digit of 5^55 is 5
unit digit of 8^88 is 6
adding will give 15
unit digit is therefore 5....
hope it helps
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