Math, asked by Nwokoyepatrick, 8 months ago

The last term l of a geometric progression with n terms and a common ratio r is given by l=arn-1, where a is the first term. Given l, n and r, find a.

Answers

Answered by Anonymous
1

\huge\bigstar\sf\red{Answer:}

\sf{In \ Geometric \ progression, }

\sf{First \ term=a,}

\sf{Common \ ratio=r,}

\sf{r=\dfrac{t_{n+1}}{t_{n}}}

\sf{Last \ term=ar^{n-1}}

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