Question

The last term of an arithmetic sequence is 82, the common difference is 4 and the number of terms is 23. What is the first term of the sequence?

Answer 1

Answer:

-6

Step-by-step explanation:

Given - last term(tn) = 82, (d) = 4 and n = 23

tn = a+(n-1)d

82 = a+(23-1)4

82=a+22*4

82=a+88

a=82-88

a = -6

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