The last term of the series in AP is 31 the sum is 136 and common difference is 4.find the value of first term and the numbers of term in series.
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Sn =136 n= 31 d=4
Sn=n/2 [2a +{n - 1}d]
136 =31/2 [2a +{31 -1}4]
136 x 2 =31 {2a +120]
272 = 62a + 3720
272-3720 =62a
-3448/62 =a
-55 x 38/62 [mixed fraction]
Step-by-step explanation:
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