Question

the last term of the series1,2,4..... to10 terms is​

Answer 1

The given series forms a geometric progression whose

common ratio, r=2  

nth term of GP=ar^n-1

10th term = 1×2^9 = 512

Answer 2

Step-by-step explanation:

1,2,4,8,16,32,64,128,256,512,1024,2048,

4096

$formula - n \times 2$