Chemistry, asked by sumaiya5552, 1 year ago

The latent heat of vaporization of water is 9700 ca/mol if the boilling point of water is 100 degree celcius the ebullioscopic constant of water is

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Answered by UrvashiBaliyan
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Answer:

The latent heat of vaporization for water is 22.6 x 10^5 J/kg. This means that 22.6 x 10^5 J of heat energy must be added to turn one kilogram of water from liquid to gas at 100 degrees Celsius. This graph shows how the temperature of water changes with added heat.

Answered by nrathour769
0

The latent heat of vapourisation of water is 9700 Cal / mole and if the b.p. is 100 째C, ebullioscopic constant of water is [CBSE PMT 1989] (a) 0.513째C kg/mol (c ...

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