the lateral surface are of a hollow cylinder is 4224 cm square, it is cut along it's height and formed a rectangular sheet of width 33 cm. find the perimeter of rectangular sheet .
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hiii!!!
here's ur answer...
the CSA of the cylinder is 4224cm² and it's cut along is height and form a rectangular sheet.
therefore the area of the rectangular sheet will be the area of CSA of the hollow cylinder.
so area of the rectangular sheet is 4224cm².
breadth (width) of the rectangular sheet is 33cm.
therefore length×breadth=4224cm²
→ length × 33 = 4224cm²
→ length = 4224/33
→ length = 128cm
★ VERIFICATION ★
area of rectangular sheet=l×b
=128×33
=4224cm²
hence verified
thus the length of the rectangular sheet is 128cm.
perimeter of the rectangular sheet = 2 (l + b )
= 2 ( 128 + 33 )
= 2 × 161
= 322cm
hope this helps u..!
<<<<<<☺☺☺>>>>>>
here's ur answer...
the CSA of the cylinder is 4224cm² and it's cut along is height and form a rectangular sheet.
therefore the area of the rectangular sheet will be the area of CSA of the hollow cylinder.
so area of the rectangular sheet is 4224cm².
breadth (width) of the rectangular sheet is 33cm.
therefore length×breadth=4224cm²
→ length × 33 = 4224cm²
→ length = 4224/33
→ length = 128cm
★ VERIFICATION ★
area of rectangular sheet=l×b
=128×33
=4224cm²
hence verified
thus the length of the rectangular sheet is 128cm.
perimeter of the rectangular sheet = 2 (l + b )
= 2 ( 128 + 33 )
= 2 × 161
= 322cm
hope this helps u..!
<<<<<<☺☺☺>>>>>>
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