Question

The LCM and HCF of two number are 432 and 72 respectively. If one of of the numbers is 216, what is the other

Answer 1

Let LCM=432 and HCF =72

Let one number is “a”=216 and the other number is “b” which is unknown as b=?

To find b we as

LCM=a×b/HCF

LCM ×HCF /a=b putting the value we get

432×72/216=b

Therefor:

b=144

So the other number is 144.

Answer 2

Answer:

Here, LCM = 432, HCF = 72, First number = 216  First number x Second number = LCM x HCF  ∴ 216 x Second number = 432 x 72  ∴ Second number = (432 x 72)/216  = 432 x 72/216  = 432 x 1/3  = 144 ∴ The other number is 144.

Step-by-step explanation:

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