Question

the LCM and HCF of two numbers are 156 and 4 respectively if one number is 52 find the other number​

Answer 1

We already knew a formula for 2 numbers, i.e., the product of LCM and HCF of two numbers a and b is equal to the product of the two numbers (a and b).

Arithmetically:

LCM × HCF = a × b

So, Now let's look at the question;

Here, we are given the LCM, HCF and a number

Now, We have to find the other number; So, let's plug them in;

LCM × HCF = a × b

⇒ 156 × 4 = 52 × b

Now let's Simplify the above equation;

624 = 52b

Now, as we have to isolate "b", we'll divide both the sides with 52;

$\dfrac{52\text{b}}{52} = \dfrac{624}{52}$

Simplify. :)

b = 12

Therefore the other number is 12.