the [LCM multiply HCF]
of 48, 72, 108
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Given numbers are 48, 72 and 108 Factorization of 48, 72 and 108 Here, 22 × 31 are the smallest powers of the common factors 2 and 3 respectively. So, HCF (48, 72, 108) = 2 × 2 × 3 = 12 24 × 33 are the greatest powers of the prime factors 2 and 3 respectively involved in the given three numbers . LCM of these three integers = 2 × 2 × 2 × 2 × 3 × 3 × 3 = 432
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Answer:
LCM of 48, 72 and 108
=2×2×2×3×3×2×1×3
=2×2×2×2×3×3×3
=16×27
=432
Step-by-step explanation:
@Genius
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