The LCM od two numbers is 14 times their HCF . the Sum of LCM and HCF is 600. If one number is 280 , then find the other number
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hey friend !!
here's your answer :-
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Given that ,
● The LCM of two numbers is 14 times of their HCF .
==> LCM = 14 HCF ..............( 1 )
● The sum of the LCM and HCF is 600.
==> LCM + HCF = 600 ..............( 2 )
Put the value of LCM ( 1 ) in second ( 2 ) eq.
==> 14 HCF + HCF = 600
==> 15 HCF = 600
==> HCF = 600 / 15
==> HCF = 40
● hence , HCF = 40
Put the value of HCF in 1st eq.
==> LCM = 14 HCF
==> LCM = 14 * 40
● hence , LCM = 560
□ Given that , if
One number = 280
Second number = ?
As we know that ,
☆ LCM * HCF = first number * second number
On putting values , we get :-
==> 560 * 40 = 280 * second number
==> second number = ( 560 × 40 ) / 280
==> second number = 2 × 40
==> second number = 80
hence , second number is 80.
________________________
hope it helps !!
thanks for asking :)
☆ be brainly ☆
here's your answer :-
________________________
Given that ,
● The LCM of two numbers is 14 times of their HCF .
==> LCM = 14 HCF ..............( 1 )
● The sum of the LCM and HCF is 600.
==> LCM + HCF = 600 ..............( 2 )
Put the value of LCM ( 1 ) in second ( 2 ) eq.
==> 14 HCF + HCF = 600
==> 15 HCF = 600
==> HCF = 600 / 15
==> HCF = 40
● hence , HCF = 40
Put the value of HCF in 1st eq.
==> LCM = 14 HCF
==> LCM = 14 * 40
● hence , LCM = 560
□ Given that , if
One number = 280
Second number = ?
As we know that ,
☆ LCM * HCF = first number * second number
On putting values , we get :-
==> 560 * 40 = 280 * second number
==> second number = ( 560 × 40 ) / 280
==> second number = 2 × 40
==> second number = 80
hence , second number is 80.
________________________
hope it helps !!
thanks for asking :)
☆ be brainly ☆
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