Math, asked by Gouravrothaki5230, 1 year ago

The LCM of a b is 36 , HCF is one then find the possible values of a b

Answers

Answered by parthiv2002

0

Answer:

LCM×HCF=a×b

36×1=a×b

so a=36

b=1

HCF 1 and LCM 36

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