Question

the LCM of no 1890and HCF of 30 and one of them is 270 and find other no.​

Answer 1

Step-by-step explanation:

HCF=30

LCM=1890

one number is=270

let another number be =x

HCF×LCM=Product of numbes

30×1890=270×x

(30×1890)/270=x

210=x

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Answer 2

Answer:

210

Step-by-step explanation:

LCM × HCF = Product of the numbers.

let the other no. be x

1890×30 = 270x

56700 = 270x

x = 56700/270

x = 210.

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