Math, asked by ngaihzualatsi, 4 months ago

The LCM of the polynomial (x-1)² (x+2) (x+7)³ and (x+1) (x+2)² is

(a) (x-1) (x+2) (x+7)
(b) (x-1)² (x+2) (x+7)³
(c) (x+1) (x-1)² (x+2)² (x+7)³
(d) (x+1) (x-1)² (x+2)² (x+7)³

Answers

Answered by rupad846
0

c is a wright. answer ok

Answered by pulakmath007
3

SOLUTION

TO CHOOSE THE CORRECT OPTION

The LCM of the polynomial

(x-1)² (x+2) (x+7)³ and (x+1) (x+2)² is

(a) (x-1) (x+2) (x+7)

(b) (x-1)² (x+2) (x+7)³

(c) (x+1) (x-1)² (x+2)² (x+7)³

(d) (x+1) (x-1)² (x+2)² (x+7)³

EVALUATION

Here the given two expressions are

(x-1)² (x+2) (x+7)³ and (x+1) (x+2)²

Now in the above two expressions

Highest exponents of (x-1) is 2

Highest exponents of (x+2) is 2

Highest exponents of (x+7) is 3

Highest exponents of (x+1) is 1

Hence the required LCM

= (x+1) (x-1)² (x+2)² (x+7)³

FINAL ANSWER

The correct option is

(c) (x+1) (x-1)² (x+2)² (x+7)³

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