The LCM of two coprime number is 5005 if one of the number is 65 then find the other number
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51
let the other number be x
since the lcm is 5005 and one number is 65
we know that the numbers are co primes
so HCF = 1 because co primes have only one 1 as their common factor
using equation HCF ×LCM =PRODUCT OF TWO NUMBERS we get
1 × 5005= 65 × other number
so other number = 5005/ 65= 77
so the required number is 77
since the lcm is 5005 and one number is 65
we know that the numbers are co primes
so HCF = 1 because co primes have only one 1 as their common factor
using equation HCF ×LCM =PRODUCT OF TWO NUMBERS we get
1 × 5005= 65 × other number
so other number = 5005/ 65= 77
so the required number is 77
Answered by
3
Answer:
77
Step-by-step explanation:
LCM of two co-prime Number =5005
One Number 65
As we know,
HCF ×LCM /given Number =other Number
HCF of two co-prime number is 1
Required number= 1×5005/65
=77
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