The LCM of two number is 14times their HCF. The sum of LCM and HCF is 600. If one number is 280,then find the other number
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2
Answer:
80
Step-by-step explanation:
Let the LCM=x and HCF=y and the other number=z
Then, x=14y
We know that LCM×HCF=Product of the numbers
(x)×(y)=280×z
14y×y=280z
14y²=280z
y²=20z → (1)
Also,
x+y=600
14y+y=600
15y=600
y=40
Substituting this in (1)
40²=20z
1600=20z
z=80
So, the other number is 80
Answered by
0
Let HCF of two no.s be X
LCM=14X
ATQ
14X+X=600
15x=600
X=600/15=40
hcf =40Lcm =14*40=560
product of no.s =hcf*lcm
280*y=40*560. (let other no be y)
y=40*560/280=80.
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