Question

The LCM of two numbers is 1470 and their HCF is 7. If one of the numbers is 49, the other number is​

Answer 1

Answer:

Step-by-step explanation:

As we know

Lcm × Hcf = a×b

1470×7= 49× b

b=210

The other number is 210

Answer 2

Aɴꜱᴡᴇʀ

The other number is 210

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Gɪᴠᴇɴ

The LCM of 2 numbers is 1470 and their HCF is 7.One number = 49

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ᴛᴏ ꜰɪɴᴅ

The other number?

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Sᴛᴇᴘꜱ

As it is given that the LCM of 2 numbers is 1470, the HCF of the two numbers is 7,and if one one of its number is given we can actually easily find the other number

For that we use the formula

$\sf \bf{}lcm \: \: \times hcf = the \: product \:of \: 2 \: numers$

Here let us assume that the other number is'x'

So substituting the given values we get,

$\sf \implies1470 \times 7 = 49 \times x \\ \\ \sf{} \implies 10290 = 49x \\ \\ \sf \implies \ \frac{ \cancel{10290}}{ \cancel{49}} \\ \\ \sf thus \: the \: other \: number \: is \: \: \huge \boxed{ \fbox{\bold{210}}}$

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$