The LCM of two numbers is 210 and their HCF is 14. How many such pairs are possible
Answers
Step-by-step explanation:
first divide
210 /14
formula LCM / HCF
15 Answar
Two pairs (14 , 210) and (42 , 70) are possible
Given :
The LCM of two numbers is 210 and their HCF is 14.
To find :
The number of such possible pairs
Concept :
HCF :
For the given two or more numbers HCF is the greatest number that divides each of the numbers
LCM :
For the given two or more numbers LCM is the least number which is exactly divisible by each of the given numbers
Relation between HCF and LCM :
HCF × LCM = Product of the numbers
Solution :
Step 1 of 2 :
Form the equation to find number of possible pairs
Here it is given that LCM of two numbers is 210 and their HCF is 14.
Let the numbers are 14m and 14n where m and n are co-primes
HCF × LCM = Product of the numbers
⇒ 210 × 14 = 14m × 14n
Step 2 of 2 :
Find number of possible pairs
210 × 14 = 14m × 14n
⇒ 14m × 14n = 210 × 14
⇒ m × n = 210/14
⇒ m × n = 15
Since m and n are co-primes
∴ m = 1 , n = 15 and m = 3 , n = 5
So possible pairs are (14 , 210) and (42 , 70)
Hence two pairs (14 , 210) and (42 , 70) are possible
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