Question

The LCM of two numbers is 2310 and their HCF is 33. If one of the numbers is 330 find the other number.

Answer 1

lcm×hcf= frist×second
=2310×33=330×second n.
s.n.=2310×33/330
=second number is 231


hope it is helpful for you.

Answer 2

Hey mate ^_^

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L.C.M = 2310

H.C.F = 33

One number = 330

H. C. F ( L. C. M ) = Product of two numbers

$33 ( 2310 ) = 330 ( x ) \\ \\ \frac{33}{330}( 2310 ) = x \\ \\ \frac{1}{10} ( 2310 ) = x \\ \\ x = 231$

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