Math, asked by NATIONALENVIROCLEAN, 1 year ago

The LCM of two numbers is 28 times of their HCF the sum of their LCM and HCF is 1740 one number is 240 find other

Answers

Answered by arvindkumar14
52

lcm=hcf×28

=lcm:hcf=28:1

=lcm=28x

=hcf=x

Now

lcm+hcf=1740

=28x+x=1740

29x=1740x=60

=lcm=28x=28×60

=hcf=x=60

=first number=240

second number =lcm×hcf/first number

= 28×60×60/240

=7×60=420

u r ans

Answered by Anonymous
79

\bold{\underline{\underline{Assume\::}}}

Let the -

  • other number be "M"

\bold{\underline{\underline{Solution\::}}}

Given :

  • LCM is 28 times HCF
  • Sum of LCM and HCF is 1740
  • One number is 240.

Find :

Other number.

According to question,

⇒ LCM = 28 × HCF ____ (eq 1)

Also,

⇒ LCM + HCF = 1740

⇒ 28HCF + HCF = 1740 [From (eq 1)]

⇒ 29HCF = 1740

⇒ HCF = 60

Substitute value of HCF in (eq 1)

⇒ LCM = 28 × 60

⇒ LCM = 1680

Now,

Product of two numbers = LCM × HCF

Product of two numbers = one number × other number

Substitute the known values in above formula

⇒ 240 × M = 1680 × 60

⇒ M = (1680 × 60)240

⇒ M = 7 × 60

⇒ M = 420

Other number is 420.

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