Question

The LCM of two prime numbers x and y, (x>y) is 161. The value of 3y-x is
a. 2
b. 0
c. -2
d. 1​

Answer 1

Answer:

105Q:

L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is :

A) -2

B) -1

C) 1

D) 2

Answer: A) -2

Explanation:

H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161.

Let the numbers be a and b . Then , ab= 161.

Now, co-primes with product 161 are (1, 161) and (7, 23).

Since x and y are prime numbers and x >y , we have x=23 and y=7.

Therefore, 3y-x = (3 x 7)-23 = -2